Section+1.4

(Answers by Laura, Abby and Jane) || Student Feedback || Teacher Feedback || of (f/g)(x) ||  || Correct || to "both" domains and not "either" domain. Because if Domain f is positive reals and Domain g is all reals, if you have a product of - 4 this is not in the domain of f, so the domain of this product function would have to be positive reals or (what is in both the domain of f and of g) ||  || Correct - nice explanation! || f(g(x))=(x/2)+1 does not necessarily equal g(f(x))=(x+1)/2 ||  || Correct - composition is not commutative || denominator of 0 because that is undefined, so if x=4 the denom. will be zero, and if x is any positive number greater than 4, the denom. will be a neg. number, therefore the domain must be anything less than 4, and not including 4. ||  || Correct || positive and x could be positive or negative, so that eliminates options A, C, D and E because C is the only way you would end up with a positive answer even if x is positive or negative to begin with. ||  || Correct - again, nice explanation! ||
 * Student Answers
 * 45. False: if g(x)=0, x is not in the domain
 * 46. False; it should say all numbers belong
 * 47. C; example: f(x)= x+1 g(x)= x/2
 * 48. A; you cannot have a fraction with the
 * 49. E; solve (x^2+1)^2 +1 ||  || Correct ||
 * 50. B; if y=abs(x) then you know y MUST be