Section+2.2

(Answers provided by Michael and Ammar) || Student Feedback || Teacher Feedback || y-axis, meaning that this function is even || Correct || has 1 unique value of y || Correct || you take the reciprocal of the function, so it becomes (1/2x) to the positive (1/2) power. The function becomes 2x4 square root The answer is the square root of 16 which is 4 || Incorrect .. the answer is A .. the negative one-half power only has x as a base, not (2x). || is 1/2x to the (1/2) power. To remove the fractional exponent one half, thake the power of the numerator and take that answer and use the denominator as your root. This funtion rewritten is y=1/ the square root of 2x. If x equals 4 then then two x equals 8. The square root is 2 root 2 and all of this over 1 || Incorrect ... the answer is E. 0 to the negative one-third power is 1 over 0 to the one-third power (which is 0 in the denominator) || the three-halves power is 0. ||
 * Student Answers
 * 58.True || Function is even because it is symmetric to the
 * 59.False || Function is not symmetric over y-axis. Each value of x
 * 60.E || The function is y=2x to the negative (1/2) power. To remove the negative power,
 * 61.D || The function y=2x to the negative one-half power (-1/2) when rewritten to remove the negative exponent
 * 62.B || The function y=x to the (2/3) power is an even function. Rewriting the equation we get the cube root of x square. Making a tabvle of x values from -2-2, we get the y value (1.587) for -2 and 2, (1) for -1 and 1 and (0) for 0. Their is one value of y for two values of x: X and -X (not counting 0). This is an even function || Correct ||
 * 63. C || The function y=x to the (3/2) power when rewritten is the square root of x cubed. You can not take the square root of a negative number. The answer is either B or C. The final answer is C because c is saying that you can use the value of 0 in this function || Incorrect ... answer is B ... 0 to